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The Solar Year of the Coligny Calendar a.pdf


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Method of sequential use
The solar year on the plate, as shown in the previous essay, contains 366 days,
or 367 if Equos is long. If Equos is given 30 days in (Gaulish) years encompassing a Roman bissextile, and 29 days in other years, as Fotheringham suggested (Fotheringham 1910, 285-6), then this solar year will always amount to
a Roman year and a day, and will advance on the Roman calendar by one day
per year. After 30 years, it will have advanced by 30 days; and at this point,
omitting one 30-day intercalary month should cause the pattern to repeat.
To illustrate, let us take a single day in the Gaulish solar year – say, the first day of
solar Samon – and determine its Roman equivalents over a 30-year period.

Results of sequential use
As shown in the previous essay, the intercalary months indicate the days on which
solar Samon commences in the five ‘plate-years’:
TABLE 1: Days on which solar Samon begins in the five plate-years
Plate-

Start of

year

solar Samon

III

Samon 25

I

II

IV
V

Samon 1

Samon 13
Samon 7

Samon 19

Now let us arbitrarily call March 1, AD 101 ‘Samon 1 of cycle-year 1’, and
observe the behaviour of these five days against the Roman calendar:
TABLE 2: Results of sequential use (cycle-years 1 to 5)
Cycleyear

Start of

Roman

Year II, Samon 13

March 02, 102

solar Samon

1

Year I, Samon 1

4

Year IV, Samon 7

2
3

5

Year III, Samon 25
Year V, Samon 19

Long

equivalent

Equos?

March 03, 103

Y

March 01, 101

March 04, 104

March 05, 105

As can be seen, these five starting-days of solar Samon occur at intervals of a
Roman year and a day, such that the equivalent day of March increments by one
day per year. Making Equos long in bissextile years preserves this pattern.

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